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0=7x^2-2x-6
We move all terms to the left:
0-(7x^2-2x-6)=0
We add all the numbers together, and all the variables
-(7x^2-2x-6)=0
We get rid of parentheses
-7x^2+2x+6=0
a = -7; b = 2; c = +6;
Δ = b2-4ac
Δ = 22-4·(-7)·6
Δ = 172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{172}=\sqrt{4*43}=\sqrt{4}*\sqrt{43}=2\sqrt{43}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{43}}{2*-7}=\frac{-2-2\sqrt{43}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{43}}{2*-7}=\frac{-2+2\sqrt{43}}{-14} $
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